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Thread: displaying an image as a variable

  1. #1

    displaying an image as a variable

    How should this be written to display (not download) tiger.jpg.

    $file = 'tiger.jpg';

    echo("<img src=\"$file\" />");


  2. #2
    Looks fine since the html source would be...
    <img src="tiger.jpg" />
    If you wanted a link to the image then try this...
    echo("<a href=\"$file\">$file</a>");

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