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Thread: Redundant code help

  1. #1

    Redundant code help

    Can someone consolidate this code:

    Maybe as a funtion or something.

    I know there has to be a better way of doing this. Im not very good at AS.
    Ill offer you 10-15 bucks for the first person who can give me a working answer. Thanks for your time! I have lot of other stuff I need help with too.


    if (_root.TQ1Completed == "6") {
    TQcheckMark1._visible = true;
    } else {
    TQcheckMark1._visible = false;
    if (_root.TQ2Completed == "5") {
    TQcheckMark2._visible = true;
    } else {
    TQcheckMark2._visible = false;
    if (_root.TQ3Completed == "4") {
    TQcheckMark3._visible = true;
    } else {
    TQcheckMark3._visible = false;
    if (_root.TQ4Completed == "3") {
    TQcheckMark4._visible = true;
    } else {
    TQcheckMark4._visible = false;
    if (_root.TQ5Completed == "4") {
    TQcheckMark5._visible = true;
    } else {
    TQcheckMark5._visible = false;

    The "numbers" correspond to the number of sections in the question.
    For example "TQ1Completed" has "6" sections and so on.

  2. #2
    Hello, I don't really get what you want in the if statement (ex: == "4") How is "4" determined?

    tqstart = 1;
    tqend = 5;
    for (i=tqstart; i<=tqend; i++){
    if (_root["TQ" + i + "Completed"] == idontgetwhatyouwanthere){
    _root["TQcheckMark" + i]._visible = true;
    _root["TQcheckMark" + i]._visible = false;

    Wait, I think this is what you want:

    sections = array(6,5,4,3,4);

    for (i=0; i<sections.length; i++){
    if (_root["TQ" + (i+1) + "Completed"] == sections[i]){
    _root["TQcheckMark" + (i+1)]._visible = true;
    _root["TQcheckMark" + (i+1)]._visible = false;

    Last edited by freeskier89; November 19th, 2005 at 01:59 AM.

  3. #3
    freeskier89 thanks for the quick reply.

    I type this number (ex: == "4") in by hand.

    The (ex: == "4") corresponds to the amount of sections in the teaching question.

    So (ex: == "4") has 4 sections in the teahing question.



  4. #4
    Did you check my edited post?
    Is that what you want?

  5. #5
    Oh crap that was fast.
    That looks about right. Im gonna try it.

    PM me your pay pal address please.


  6. #6
    Ok I just realized you might need a "new" in front "array"

    sections = new Array(6,5,4,3,4);

    for (i=0; i<sections.length; i++){
    if (_root["TQ" + (i+1) + "Completed"] == sections[i]){
    _root["TQcheckMark" + (i+1)]._visible = true;
    _root["TQcheckMark" + (i+1)]._visible = false;

    Hope it works

  7. #7
    Did i do this right?

    I needed to target the same timeline the script was in so I used "this" on the _visible commands and it worked. Is that ok? or should I use something else?

    sections = new array(6, 5, 4, 3, 4);
    for (i=0; i<sections.length; i++) {
    if (_root["TQ"+(i+1)+"Completed"] == sections[i]) {
    this["TQcheckMark"+(i+1)]._visible = true;
    } else {
    this["TQcheckMark"+(i+1)]._visible = false;


  8. #8
    You've got it . "this" will work fine, and is probably the best thing to use if it is on the same timeline.

  9. #9
    im gonna just show off, lol

    this["TQcheckMark"+(i+1)]._visible = (_root["TQ"+(i+1)+"Completed"] == sections[i]);

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