Brain teasers

[Ψ]

A 30 year old man married a 25 year old woman. She died at age 50
and her husband was so devastated that he cried for years. Ten
years after he stopped crying, he died. If he had lived to be 80,
how many years was he a widower?

[wizard]

25 years?

[Jeff Wheeler]

I say 25 as well...

[Coppertop]

25 years. Here's one for you (originally, I didn't get this, because the simple logic almost completely escaped me)

An amazon explorer was paddling up the amazon river, when he spotted an ostrich egg floating downstream. Where did it come from?

[Jeff Wheeler]

an ostrich?

[Coppertop]

Yep. But I originally said upstream :trout: You're turn.

[Jeff Wheeler]

widower works ;)
http://encarta.msn.com/encnet/features/dictionary/DictionaryResults.aspx?refid=1861713155

[Coppertop]

Yes upstream, it was floating downstream, there for it must have come from upstream!

edit: yeldarb, where'd your post go?

[Yeldarb]

People already answered lol -- I deleted it :P

[Coppertop]

But now I look like a skitzo! :P

[Ψ]

ok it was 25

[Jeff Wheeler]

Burning rope

There are two lengths of rope.
Each one can burn in exactly one hour.
They are not necessarily of the same length or width as each other.
They also are not of uniform width (may be wider in middle than on the end), thus burning half of the rope is not necessarily 1/2 hour.

By burning the ropes, how do you measure exactly 45 minutes worth of time?

If you light both ends of one rope, it will burn in exactly a 1/2 hour. Thus, burn one rope from both ends and the other rope from only one end. Once the one rope (which is burning from both ends) finally burns out (and you know a 1/2 hour has elapsed), you also know that the other rope (which is buring from only one end) has exactly 1/2 hour left to burn. Since you only want 45 minutes, light the second end of the rope. This remaining piece will burn in 15 minutes. Thus, totaling 45 minutes.

[Ψ]

Two mothers and two daughters were fishing. They managed to catch
one big fish, one small fish, and one fat fish. Since only three
fish were caught, how is it possible that they each took home a fish?

[iLikePie]

ooh i think i worked it out...

what if you light both ends of one rope, and just one end of the other. Then, when the first rope has finished (half an hour) you light the other end of the other rope (which will be about half burnt) and thus speed up it's burning...
that would equal 45mins right?

[Jeff Wheeler]

two of them took one home together ;P

[iLikePie]

they drowned one of the people before they left, so there were only 3 going home?!?!

[Ψ]

no
you guyz give up or wut
.well i have to go so ill give you the answer
The fishing party consisted of three people. A grandmother, a
mother, and a daughter. The mother is both a mother and a
daughter.

[El_Thierro]

It was a grandma, her daughter and the grandchild.

Thus, two mothers and two daughters, but only three persons?

:beam:

[El_Thierro]

GRRR!!! I knew it! Look at the times!!! *points in anger*

WE POSTED AT THE SAME TIME!! GRRRR! :m:

:sure: :P

[Coppertop]

and i have a whole bunch more: who played for both england and france on the same afternoon in the wembly stadium?

[Jeff Wheeler]

the ref? ;P

[El_Thierro]

The opening band/singer thingy? ;P ;P

[Coppertop]

The opening band/singer thingy? ;P ;P:party: WE HAVE A WINNER! :party:

(the ref doesn't play ;))

[El_Thierro]

Yay! :party: lol

You go ahead though, it's 2:18am here and I don't know any by heart and I'm too tired to look for some :beam:

I'm off to bed even. G'night :sleep:

[Coppertop]

Sure thing cheif!


What can you find at the centre of paris that can't be found in London or Milan?

[El_Thierro]

The Eiffel Tower? :lol:

Now I'm really going.

[jtnw]

Sure thing cheif!


What can you find at the centre of paris that can't be found in London or Milan?
The letter 'r'?

jtnw

[Coppertop]

The letter 'r'?

jtnw

:party: We have a winner! :party:

welcome to the boards!

[Maxtr0sity]

How much wood would a woodchuck chuck, if a woodchuck could chuck wood?












As much wood as a woodchuck would, if a woodchuck could chuck wood.

[ViNc3]

lol, I only knew the first part of that...never knew there was an actual answer :P

[Ψ]

arrite people heres another
If there are fifteen crows on a fence and the farmer shoots a
third of them, how many are left?

[El_Thierro]

None, coz he'll startle all of them which 'll cause them all to fly away :beam:

[Yeldarb]

What if the crows are stapled to the fence?

[El_Thierro]

Who in the right mind would staples crows to a fence :huh:

[jokun]

the farmer would have to if he was planning on shooting a third of them.


oh, and if a wood chuck could chuck, a wood chuck would chuck, if a wood chuck could chuck wood.

[Hans Kilian]

I love statistical ones:
You have four cards - two red and two black. You mix them and draw two cards at random. What is the statistical likelihood that the cards are the same color?

Edit: Same color in this regard means either both black or both red. Ignore suits.

[DarkChild]

1/12th i guess...

[jtnw]

2/5ths?

jtnw

[firegambler]

it's calculated as follows:
wanted ones divided by possible ones.
then you have to multiply the results of each time you drew.

first draw: 1/4
second draw: 1/3

1/4 * 1/3 = 1/12

1/12 is the result.

[jtnw]

That includes duplicates though, right? ie 1 & 2 vs 2 & 1

jtnw

[paradox244]

actually the likelihood of them being the same (without regard for one color or the other) is 1/3, had you asked what is the likelihood of them both being red, then it would have been 1/12th. As the question is asked the first card doesn't really count, as it just determines what the other card has to be in order to match.

[Hans Kilian]

Paradox is right. The answer is 1/3. Lots of people say 1/4 or 1/2.

You can do the same with children. If a couple have two children and one of them is a boy, what is the likelihood that the other is a boy as well. That answer is 1/3 as well.

[Ψ]

nother one fer u fellas
A man is wearing black. Black shoes, socks, trousers, jumper,
gloves, and balaclava. He is walking down a black street
with all the street lamps off. A black car is coming toward him
with its lights off too, but somehow manages to stop in time. How
did the driver see the man?

[jtnw]

It's daytime. ;)

jtnw

[wizard]

He didn't, the man was walking on the sidewalk and was never in any kind of danger... duh :sigh:




:P

[Ψ]

nice one how did you noe jtnw
arrite another one for you peeps
How would you rearrange the letters in the words new door to make one
word? Note: There is only one correct answer.

[jtnw]

azzy, I've heard most of these before. I know the new door one, but I'll let others have a chance at it.

jtnw

[El_Thierro]

Just arrange them and make "one word"?

as in "new door" ---> *arranges* ----> "one word" :beam:

:bad:

[Ψ]

ding ding ding we have a winner

[Yeldarb]

Paradox is right. The answer is 1/3. Lots of people say 1/4 or 1/2.

You can do the same with children. If a couple have two children and one of them is a boy, what is the likelihood that the other is a boy as well. That answer is 1/3 as well.No it's not, it's 1/2 :P
It's either a boy or a girl.

[Ψ]

arrite men heres another one.
three ants were going under a door and two or them could pass by. why coudnt the third one go

[El_Thierro]

Someone opened the door ;P

I didn't understand the sentence in the first place :ne:

[Ψ]

no you silly the third ant was wearing high heel sandals

[eilsoe]

because it was really really fat?

because it had claustrophobia?


=)

[Hans Kilian]

No it's not, it's 1/2 :P
It's either a boy or a girl.

The trick is in the wording. If you said 'If the first child is a boy, what is the chance that both of the children are boys?', then the answer is 1/2.

But when you say 'If one of the children is a boy, what is the chance that both the children are boys?', then the answer is 1/3.

There are four equally likely combinations that you can have 2 children.
1) first child is a boy, second child is a boy
2) first child is a boy, second child is a girl
3) first child is a girl, second child is boy
4) first child is a girl, second child is girl

In three of the combinations, one of the children is a boy (1, 2 and 3). But only in one of the three (no. 1) are both children boys. So the answer is 1/3.

I have a mate that still - after several years - insists that the answer is 1/2 :)

[andr.in]

But when you say 'If one of the children is a boy, what is the chance that both the children are boys?', then the answer is 1/3.

There are four equally likely combinations that you can have 2 children.
1) first child is a boy, second child is a boy
2) first child is a boy, second child is a girl
3) first child is a girl, second child is boy
4) first child is a girl, second child is girl
I have a mate that still - after several years - insists that the answer is 1/2 :) I insist it to be 1/2 as well!

the 2nd and the 3rd are identical! IF you have 1 boy then the next one can be either a boy or a girl... it doesn't matter if the boy is the "first" or the "second" one.

ok...
If the "first" one is a boy then you're left with variants 1 and 2 (SEE? only 2!), if the boy is the "second" one then you're left with varianbts 3 and 1 (oh look! 2 again!) ... so the answer is definitely 1/2 ;P

[pom]

The trick is in the wording. If you said 'If the first child is a boy, what is the chance that both of the children are boys?', then the answer is 1/2.

But when you say 'If one of the children is a boy, what is the chance that both the children are boys?', then the answer is 1/3.

There are four equally likely combinations that you can have 2 children.
1) first child is a boy, second child is a boy
2) first child is a boy, second child is a girl
3) first child is a girl, second child is boy
4) first child is a girl, second child is girl

In three of the combinations, one of the children is a boy (1, 2 and 3). But only in one of the three (no. 1) are both children boys. So the answer is 1/3.

I have a mate that still - after several years - insists that the answer is 1/2 :)Nice one :) Very tricky.

Here's one of my favorite:
I have 5 hats in my hands. 3 of them are white, 2 of them are black. In front of me are standing Senocular, Kirupa and Lostinbeta. I put one hat on each head, so that they can see the color of the other people's hat but not their own. I ask them what the color of their hat is.
Senocular, seeing a white hat on Kirupa's head and a white hat on Lost's head, and noticing that neither of them can answer the question, says "I'm wearing a white hat". Now how did he know that ?

PS: This brain teaser assumes that Senocular is a bit more clever than his 2 contestants :love:

[hsadan]

um, you're still holding the 2 black hats and sen notices that? =)

[DarkChild]

I insist it to be 1/2 as well!

the 2nd and the 3rd are identical! IF you have 1 boy then the next one can be either a boy or a girl... it doesn't matter if the boy is the "first" or the "second" one.

ok...
If the "first" one is a boy then you're left with variants 1 and 2 (SEE? only 2!), if the boy is the "second" one then you're left with varianbts 3 and 1 (oh look! 2 again!) ... so the answer is definitely 1/2 ;P
well yeah, 2 identical combinations aren't taken in account as a possibility, so definately 1/2...

[Hans Kilian]

I insist it to be 1/2 as well!

the 2nd and the 3rd are identical! IF you have 1 boy then the next one can be either a boy or a girl... it doesn't matter if the boy is the "first" or the "second" one.

ok...
If the "first" one is a boy then you're left with variants 1 and 2 (SEE? only 2!), if the boy is the "second" one then you're left with varianbts 3 and 1 (oh look! 2 again!) ... so the answer is definitely 1/2 ;P

I'll admit that it's a tricky one... But the answer is 1/3 :)

You can turn it into a bar bet and win beers with it. Take two coins and say "I'll flip these two coins. If one of the coins is heads, then I bet that the other is tails". You'll win two out of three bets.

If you don't believe me, then take two coins and a piece of paper and start flipping. The pattern should show up pretty fast.

Another way of looking at it is to break it down into two flips:
The first coin can be head or tails. 50/50 chance.
If the first coin is heads, then the second can be heads or tails. 50/50 again. If the second is heads as well, then you lose. If it is tails, you win.
If the first coin comes up tails, and the second comes up heads, then you win. If both come up tails, then the flip is discarded since there were no heads.

So of the four possibilites, you win 2, lose 1 and 1 is discarded. So you win 2 out of 3 that aren't discarded.

[Hans Kilian]

Nice one :) Very tricky.

Here's one of my favorite:
I have 5 hats in my hands. 3 of them are white, 2 of them are black. In front of me are standing Senocular, Kirupa and Lostinbeta. I put one hat on each head, so that they can see the color of the other people's hat but not their own. I ask them what the color of their hat is.
Senocular, seeing a white hat on Kirupa's head and a white hat on Lost's head, and noticing that neither of them can answer the question, says "I'm wearing a white hat". Now how did he know that ?

PS: This brain teaser assumes that Senocular is a bit more clever than his 2 contestants :love:

I thought I knew this one, but I've seen this in another version where it's Lostinbeta that knows he's wearing a white hat even though he can't see any of the others.

[saint cleve]

easy, lost notices that kirpua and senocular are wearing white hats and hesitates becase there is a better chance that his hat is black. and kirupa notices that senocular and lost are also wearing white hats and he too hesitates because of the greater chance of his hat is to be black... then senocular with his cleverness sees that kirupa and lost are both wearing white hats and are both hesitating to answer, realizes that they are uncertain about their guess. so senocular comes to the conclusion that kirupa sees two white hats and is uncertain about his guess as is lost. so the most reasonable answer would be white.

[mlk]

nother one fer u fellas
A man is wearing black. Black shoes, socks, trousers, jumper,
gloves, and balaclava. He is walking down a black street
with all the street lamps off. A black car is coming toward him
with its lights off too, but somehow manages to stop in time. How
did the driver see the man?

could have been a colgate (insert favorite brand of toothpaste here) smile :beam:

[saint cleve]

there are 18 roosters sitting ontop of 4 hens. the 4 hens manage to escape from underneath the 18 roosters. the 4 hens all run in opposite directions, north, east, south, and west. 6 roosters chase the hen that went north, 6 roosters chase the hen that went south, 4 roosters chase the hen that went east, and 2 roosters chase the hen that went west. the hen that went north jumps over a cliff and 4 roosters follow, leading to their death. the hen that went west runs underneath a lawnmower and 2 roosters followed, leading to their death. the hen that went east jumped into a pond and 3 roosters followed. they were all eaten by giant pond creaturesthe hen that travel south got lost in the forest along with 1 rooster and eventually starved to death.the remaining roosters went back to where they were sitting on the hens and got into a fight. 4 of the roosters were killed and 2 roosters ran away. did the other three roosters become friends?

[hificopymaster]

Hang on hang on.. aren't there only two roosters left? I counted 8 total when the fight started.

[Hans Kilian]

I have 5 hats in my hands. 3 of them are white, 2 of them are black. In front of me are standing Senocular, Kirupa and Lostinbeta. I put one hat on each head, so that they can see the color of the other people's hat but not their own. I ask them what the color of their hat is.
Senocular, seeing a white hat on Kirupa's head and a white hat on Lost's head, and noticing that neither of them can answer the question, says "I'm wearing a white hat". Now how did he know that ?

PS: This brain teaser assumes that Senocular is a bit more clever than his 2 contestants :love:

If Senocular was wearing a black hat, then Kirupa and Lost would see one black and one white.
Then Kirupa would know that he's wearing a white hat because Lost is silent. Lost would say something if he could see two black hats.
Since Kirupa doesn't say anything, Sen can't be wearing a black hat. And so he says that he's wearing a white one.

The version I know is this one:
Sen, Kirupa and Lost are standing in front of me in a line, facing away from me. Sen is at the back of the line and can see Kirupa and Lost. Kirupa can see Lost. Lost can't see either of the other two.
I have 3 white and 2 black hats. I place one on each of them.
There's silence for a while and then Lost says "I'm wearing a white hat!". And he's correct.
How did he know?

(This one's easier than Ilya's, IMO)

[saint cleve]

yeah..there are only two left...

[Yeldarb]

I'll admit that it's a tricky one... But the answer is 1/3 :)

You can turn it into a bar bet and win beers with it. Take two coins and say "I'll flip these two coins. If one of the coins is heads, then I bet that the other is tails". You'll win two out of three bets.

If you don't believe me, then take two coins and a piece of paper and start flipping. The pattern should show up pretty fast.

Another way of looking at it is to break it down into two flips:
The first coin can be head or tails. 50/50 chance.
If the first coin is heads, then the second can be heads or tails. 50/50 again. If the second is heads as well, then you lose. If it is tails, you win.
If the first coin comes up tails, and the second comes up heads, then you win. If both come up tails, then the flip is discarded since there were no heads.

So of the four possibilites, you win 2, lose 1 and 1 is discarded. So you win 2 out of 3 that aren't discarded.This is true, but you said what are the chances of the cards being the same color. They could be red and red, or black and black. Therefore 2/4, 1/2.

[El_Thierro]

easy, lost notices that kirpua and senocular are wearing white hats and hesitates becase there is a better chance that his hat is black. and kirupa notices that senocular and lost are also wearing white hats and he too hesitates because of the greater chance of his hat is to be black... then senocular with his cleverness sees that kirupa and lost are both wearing white hats and are both hesitating to answer, realizes that they are uncertain about their guess. so senocular comes to the conclusion that kirupa sees two white hats and is uncertain about his guess as is lost. so the most reasonable answer would be white.
Was gonna say the exact same thing :thumb:

[hsadan]

Then Kirupa would know that he's wearing a white hat because Lost is silent.

then why does he still hesitate? :h:

[El_Thierro]

Because he's chicken! :lol:

:pa:

:run:

[pom]

Saint Cleve's "most reasonable answer" is of course wrong :P Hans is right though. And I knew the other one as well, but it's really easier :)

[pom]

Riddle me this, Batman!

Three guys check into a hotel. the clerk says it's $10 each for a room. They each give him $10 and he shows them to their rooms.

Later, he realizes that there was a special - three rooms for $25. So he takes 5 one dollar bills and goes up to the rooms. He realizes that he can't divide 5 evenly by three, so he gives each guy $1 and keeps the remaining $2 for himself.

So....

Originally, there was $30.

Each guest paid $9
3x9 = 27
The clerk kept $2
27+2=29

What happened to the other dollar?

[hificopymaster]

then why does he still hesitate? :h: That's IF sen was wearing a black hat. But he isn't.

[hificopymaster]

There is no missing dollar-

The room was $25, so each of the men paid $8.33 (1/3 of $25). The clerk keeps $2, so each man also paid $0.67 (1/3 of $2). So overall, each one of the men paid out $9, with $1 left over.
(3 * $9) + (3 * $1) = $30

[hificopymaster]

Or you could look at it like this (probably easier):

Each man paid $9. The clerk takes a $2 tip.
(3 * $9) - $2 = $25
So the clerk now has the $25 for the rooms.

Each man now has $1 left over.
The clerk still has his $2 tip.
The clerk also has the $25 for the rooms.
(3 * $1) + $2 + $25 = $30

The trick is that you can't add what one person has to what another person pays. In this case, you have to subtract.

[hsadan]

that's pretty obvious - there's no missing dollar, and you can also look at it this way:
each man had $3 left over, the clerk had $2 + their $25 for the room, so that totals $30, no big deal.

however, what I'm wondering (and what i interprete the question as) is what's wrong with the given working?

edit: oops sorry, didn't read your post cos I happened to be typing my post when you posted that :P

[pom]

There is no missing dollar-That's for sure :) The question is not to give a solution that works. It's to explain what's wrong with the solution I gave :cowboy:

[fester8542]

That's for sure :) The question is not to give a solution that works. It's to explain what's wrong with the solution I gave :cowboy:

Bah!

This friggin riddle had me screwed up for two days a couple years ago when someone told it to me.

[ViNc3]

That's for sure :) The question is not to give a solution that works. It's to explain what's wrong with the solution I gave :cowboy: You said here:


Originally, there was $30.

Each guest paid $9
3x9 = 27
The clerk kept $2
27+2=29

What happened to the other dollar? You can't add the $2 if you want to find the total money because the $2 is what the guest already paid in the $9.
What you should add is the money that was given back to the guest! ($1 x 3)

If you get what I mean...

Did I get it?? :P

[ViNc3]

Nice Riddle, btw...great post...very tricky :P

[Hans Kilian]

OK. Here's a math one:

Proof that 2 equals 1:

X = Y Given
X^2 = XY Multiply both sides by X
X^2 - Y^2 = XY - Y^2 Subtract Y^2 from both sides
(X+Y)(X-Y) = Y(X-Y) Factor both sides
(X+Y) = Y Cancel out common factors
Y+Y = Y Substitute in from line 1
2Y = Y Collect the Y's
2 = 1 Divide both sides by Y

Where is the flaw?

[saint cleve]

no way....senocular is just more clever...it said so on the post

[hificopymaster]

OK. Here's a math one:

Proof that 2 equals 1:

X = Y Given
X^2 = XY Multiply both sides by X
X^2 - Y^2 = XY - Y^2 Subtract Y^2 from both sides
(X+Y)(X-Y) = Y(X-Y) Factor both sides
(X+Y) = Y Cancel out common factors
Y+Y = Y Substitute in from line 1
2Y = Y Collect the Y's
2 = 1 Divide both sides by Y

Where is the flaw? You can't cancel the (X-Y) because X-Y is 0, given the first line. Everything after that line is meaningless, since dividing by 0 is unpredictable and crazy and mathematicians will scorn you forever if you do it. :bad:

[McGiver]

lets get backto some probability stuff.
to be unprecise: something with goats...

the event plan of a gameshow:
there are 3 doors, behind one of them is a porsche, behind the other two doors are goats.
(1) the candidate C (who doesn't know what is behind each door) picks one of the doors.
(2) the anchorman A (who knows what's behind the doors) will open one of the doors he didn't pick, and shows him the goat
(3) C can choose again
(4) C wins the price behind the door he chose

If you were the candidate - would you swap?

how likely is it that the porsche is behind the door
a) the candidate chose
b) the anchorman is offering

________________________________________

or another one (we were asked in a math test in school):
6 person are living together in a flat, distributing the work between each other from day to day. how likely is it that any of the roommates has to wash the dishes twice this week

[hificopymaster]

6 person are living together in a flat, distributing the work between each other from day to day. how likely is it that any of the roommates has to wash the dishes twice this week 100% - there are 6 people, and 7 days in a week. Someone will have to take the last day.

[hificopymaster]

To the one about the goats-

I think it's 50/50, after the anchorman shows the guy one of the goats, there's a 50/50 chance of his door having the prize behind it, no matter how many times he switches. What happened before is irrelevant, since we know that no matter which of the 3 doors he chooses, the anchorman will always cancel out one of the other doors.

[EDIT] Am I the only one who would want a goat more than a Porsche?

[McGiver]

100% - there are 6 people, and 7 days in a week. Someone will have to take the last day. yep


I think it's 50/50, after the anchorman shows the guy one of the goats, there's a 50/50 chance of his door having the prize behind it, no matter how many times he switches. What happened before is irrelevant, since we know that no matter which of the 3 doors he chooses, the anchorman will always cancel out one of the other doors. nope

[hificopymaster]

Ooh okay, I'm an idiot.

First C picks a door. The chance of the prize being there is 1/3. When A reveals one of the goats, the chance of the prize being in the other door increases to 2/3. So C should logically switch.

[McGiver]

First C picks a door. The chance of the prize being there is 1/3. When A reveals one of the goats, the chance of the prize being in the other door increases to 2/3. So C should logically switch. yep

[hificopymaster]

Here's the basic jist of one I was asked as a 6th grade math assignment:
A man goes 1km south, 1km west, 1km north, and ends up where he started. What are his two possible locations?

[Hans Kilian]

"In a maze of twisty little passages, all alike".

5 bonus points for anyone old enough to know where that is from... :)

[hificopymaster]

Colossal Cave! Although I'm not actually old enough. It was the only game my older cousins had until I was 13. :)

[Hans Kilian]

Awesome, Hificopymaster! The 5 points are yours.

I played that game to death 20 years ago. Almost got all the points. I think I missed 1 or 2. Never figured out what to do with the Rubiayat of Omar Khayam (I'm 100% sure that that's misspelled).

[firegambler]

Here's the basic jist of one I was asked as a 6th grade math assignment:
A man goes 1km south, 1km west, 1km north, and ends up where he started. What are his two possible locations?
North pole.

(South pole is not an option since you can not go south any further)

[Hans Kilian]

North pole.

(South pole is not an option since you can not go south any further)

An infinite set of options is on the circle that's approx. 1159 meters away from the south pole.

When you walk 1000 m south, you near the pole. When you walk 1000 m west, you walk in a circle around the pole (159 x 2 x Pi = 1000). Then you walk 1000 m north and end up at the same spot again.

So there's an infinite number of points near the south pole that'll work.

[hificopymaster]

Yes Hans, that's the other answer - sorry, I said two possible locations, I should have said two possible areas or two correct answers to the question "where is he?" or something other than what I said. Heh. See how I suck at wording? :P

[El_Thierro]

...

let's go back to the crow-ones :P

:ne:

[pom]

Ooh okay, I'm an idiot.

First C picks a door. The chance of the prize being there is 1/3. When A reveals one of the goats, the chance of the prize being in the other door increases to 2/3. So C should logically switch.Doh! I didn't get that :-/
First C picks a door. The chance of the prize being there is 1/3.I'm cool with that.
When A reveals one of the goats, the chance of the prize being in the other door increases to 2/3.:h: I don't see why. There are 2 doors: the one chosen by C and the one that has not been chosen. There's a posche and a goat left to find. Behind each of those doors, there's a 50 % chance you will find either one of them, no? :hangover:

[DarkChild]

yeah, the chance that C gets the porsche rises from 33,33% to 50%, thought that too

[hificopymaster]

You agree that the chance of the prize being behind his original door is 1/3 right? So the chance of the prize being in either of the other 2 doors is 2/3, since we know the prize must be in one of the 3. The other 2 doors form a subset of the original set, and the probabilities associated with that subset don't chance. So when the host shows the contestant which of those two doors has a goat behind it, the only possible place for the prize (within that set) is behind the other door. Since the probability of the prize being in that subset is 2/3 and the probability of the prize being behind the door the host opened is 0, the entire 2/3 must go to that remaining unopened door.

[hificopymaster]

It's like, if you have a deck of cards, and someone says to you, you win $100000 if you pick the ace of spades. So you pick one card at random. There's a 1/52 chance you picked the right card. Pretty slim odds there. You also know there's a 51/52 chance the right card is in the rest of the deck. Then the other guy says, "I'm gonna turn over 50 of these cards which are NOT the ace of spades, and leave one unturned. You can then choose to switch if you want." The chance of the ace of the spades being in that other part of the deck remains 51/52, no matter how many cards the guy turns over. Try it, most of the time, the unturned card will be the card you want.

[EDIT] Another way to think of it: In this deck of cards example, if you say that there's a 50/50 chance you picked the right card, you're saying that your original card will be the ace of spades 50% of the time, which is really unlikely considering you're choosing out of an entire deck.

[pom]

I'm not convinced by your explanation. Here's why: you're comparing 2 probabilities that are completely different
The probability that you find the Porsche in the first place, as you said 1/3
The probability that you find the Porsche knowing that it's not behind one of the 3 doors.For me, there's abslutely no reason to switch, because once one goat is revealed, there are 2 doors, 2 possibilities for each door, hence a 50 % percent chance you'll find the Porsche.

[pom]

It's like, if you have a deck of cards, and someone says to you, you win $100000 if you pick the ace of spades. So you pick one card at random. There's a 1/52 chance you picked the right card. Pretty slim odds there. You also know there's a 51/52 chance the right card is in the rest of the deck. Then the other guy says, "I'm gonna turn over 50 of these cards which are NOT the ace of spades, and leave one unturned. You can then choose to switch if you want." The chance of the ace of the spades being in that other part of the deck remains 51/52, no matter how many cards the guy turns over. Try it, most of the time, the unturned card will be the card you want.

[EDIT] Another way to think of it: In this deck of cards example, if you say that there's a 50/50 chance you picked the right card, you're saying that your original card will be the ace of spades 50% of the time, which is really unlikely considering you're choosing out of an entire deck.That's a good example. Funny :)

[iLikePie]

actually, i think i'm with ilyas here... i thought i understood it at first, but when you think about it, once a dud door is eliminated, there's a 50/50 chance it's in either.

Essentially, you're just picking between the two doors to begin with, since one of the duds is being removed. So, we have 2 doors left, one of them has a car, one has a goat. it doesn't matter which door he picked to begin with, there are now 2 possible options, equally likely.

no?

[hificopymaster]

Okay, look at all the possibilities:
1) door A = prize, door B = goat, door C = goat
2) door A = goat, door B = prize, door C = goat
3) door A = goat, door B = goat, door C = prize

Let's say you pick door A. You have a 1/3 chance of winning by sticking to your original choice. The host opens one of the other doors, with a goat behind it. Then the last door has a 2/3 chance of having the prize. The other 1/3 is when you have the prize behind your door and both of the other doors are goats. Do you see it now?

[Hans Kilian]

You could also look at your chance of being wrong. When you choose a door, theres 2/3 chance that you're not getting the Porsche. I think that it's pretty obvious that that chance doesn't change when one of the other doors is opened. There's still 2/3 chance that you're wrong.

So you should change doors, since there's now only 1/3 chance that you're wrong when you pick the other remaining door.

[El_Thierro]

I'd just be happy with the goat.

Geez :puzzle:

[Ψ]

I dig out tiny caves, and store gold and silver in them.
I also build bridges of silver and make crowns of gold.
They are the smallest you could imagine. Sooner or later
everybody needs my help, yet many people are afraid to
let me help them. Who am I?

[Krilnon]

You're _azzy_...

[El_Thierro]

You're _azzy_...
Either that...

...or a magic leprechaun :beam:

[Ψ]

keep guessing. i am not giving up the answer that easily

[McGiver]

a dentist

[El_Thierro]

a dentist
I think we have a winner.

[Ψ]

yes we have a winner....sob you guyz are smart /sob

[TheRhoPsi]

The rich need it,
the poor have it,
if you eat it you die.

What is it?

[El_Thierro]

Nothing! :beam:

[Ψ]

money??

[andres]

Nothing. The poor have nothing, the rich need nothing and if you eat nothing you'll die

[firegambler]

No, not money.

What do rich people need? Nothing
What do poor people have? Nothing
What happens when you eat nothing? You die.

'Nothing' is the answer, El_Thierro already said it! ;)

[firegambler]

looks as if we were posting quite at the same time :D

[andres]

looks as if we were posting quite at the same time :D
:D

[Krilnon]

I dig out tiny caves, and store gold and silver in them.
I also build bridges of silver and make crowns of gold.
They are the smallest you could imagine. Sooner or later
everybody needs my help, yet many people are afraid to
let me help them. Who am I?
Silly me, I was thinking of bridge/crown shaped molecular compounds. I guess I can imagine smaller than part of a tooth. :)

[hsadan]

Don't mind me bringing this one up, but it's been bugging me :D

Riddle me this, Batman!

Three guys check into a hotel. the clerk says it's $10 each for a room. They each give him $10 and he shows them to their rooms.

Later, he realizes that there was a special - three rooms for $25. So he takes 5 one dollar bills and goes up to the rooms. He realizes that he can't divide 5 evenly by three, so he gives each guy $1 and keeps the remaining $2 for himself.

So....

Originally, there was $30.

Each guest paid $9
3x9 = 27
The clerk kept $2
27+2=29

What happened to the other dollar?

the solution i finally came up with, happened to be the same as ViNc3

You can't add the $2 if you want to find the total money because the $2 is what the guest already paid in the $9.
What you should add is the money that was given back to the guest! ($1 x 3)

If you get what I mean...

ilyas, is this it? :)

[McGiver]

@hsadan: of course it is :)
the clerk kept 2 dollars.

27+2=29 would mean something like he paid 2$ from his own money
it has to be
27-2=25

[El_Thierro]

That's one cheap hotel.

[Ψ]

just to keep this threade alive heres another one for ou guyz

Take one out and scratch my head
I am now black but once was red.
What am I?

[firegambler]

A match!

[Ψ]

yes its is

[El_Thierro]

Another one! :beam:

[Ψ]

this one is pretty good. try to figure it out. i coudnt...i had to look at the answer

What object has keys that open no locks, space but no room, and
you can enter but not go in?

[lunatic]

A keyboard? :smirk:

[McGiver]

you guys and girl(s) are so disgusting intelligent. It's horrible! everytime I come here and can answer one of the problems someone else was faster :P

@azzy: keep on posting :D

[El_Thierro]

I know I know!

...A KEYBOARD!

:sure:

[firegambler]

Four jolly men sat down to play,
And played all night till the break of day.
They played for cash and not for fun,
With a separate score for every one.
When it came time to square accounts,
They all had made quite fair amounts.
Now, not one has lost and all have gained,
Tell me, now, this can you explain?

[Lacuna]

they, uhm. wernt playing for money?

[El_Thierro]

Three words:

Paper Monopoly Money.

[Ψ]

arrite people this one requires thinking. but its pretty easy.

There are four people that need to walk across a bridge in the
middle of the night to get to the other side. Only two people
can cross the bridge at a time and they have only 1 flashlight,
which they all must use to cross the bridge. They need to cross
the bridge and have all four people on the other side in 17
minutes. One person can cross the bridge in 1 minute, another
person can cross the bridge in 2 minutes, another in 5 minutes
and the other in 10 minutes. How do all four people get across
the bridge in 17 minutes using 1 flashlight? (No, you cannot
throw the flashlight across the bridge for the other two people
to use to cross over.)

[El_Thierro]

...make em all walk at the same time, like, really close together? :h:

Edit: k, read it again, only 2 at a time :ne:

[Ψ]

lol. its says only two people can go at once

comon man i noe you have got that brain. now is the time to use it

[lunatic]

So if the 10 minute guy and the 5 minute guy go together does that take 10 minutes? or 15 minutes?

:hr:

[MTsoul]

It'd take 10 minutes.

My dad gave me this problem and it puzzled me for months =(

[Ψ]

so you guyz give up yet or wut

[El_Thierro]

I'm thinking I'm thinking!

My brain is frying!

:sure: :sure:

[El_Thierro]

Muha, I found it! Yeehaw!

So, 1 & 2 go at the same time. It takes them 2 minutes to get there. The 1 minute guy stays at the end, the 2 min. guy returns:
4 mins.
Hands the flashlight over at the 5 & 10 min. guys. They go over in 10 mins, which makes for 14 mins. The 1 min. guy who is still there returns with the flashlight to the beginning (and the 2 min. guy) in 1 minute ---> 15 minutes.
Then the 1 minute guy and the 2 minute guy go again in 2 minutes, which makes for 17 minutes.

:beam:

[MTsoul]

Oh My God! That's So Smart!

[El_Thierro]

Oh My God! That's So Smart!
:love: :beam:

[Ψ]

you finnally got it thierro. good job.

[firegambler]

So now you're solving other people's riddles before you solve mine? :upset: :D

[Ψ]

sorry firegambler i just gave up on urs so i am posting some new ones

There is a common English word that is nine letters long. Each
time you remove a letter from it, it still remains an English
word - from nine letters right down to a single letter. What is
the original word, and what are the words that it becomes after
removing one letter at a time?

[firegambler]

Ok, the solution of my riddle is:

The four guys are playing in a dance band! :D

[firegambler]

sparkling, sparking, sparing, spring, sprig, prig, pig, pi, i

[Ψ]

hunh
:h:

[firegambler]

mark the invisible text next to "solution spoiler" to see what i wrote ;)

[Ψ]

tuff.. :D

arrite peeps heres another one



What does the following represent?
N N N N N N N
A A A A A A A
C C C C C C C

[pom]

Err... letters? :h:

[helmz]

CAN I presume?

[DarkChild]

7 cans upside down? :h:

[hydrowire]

allo, i have 3 questions(not maths, but kinda logic):

1. An airplane(flying in mid-air) ran out of fuel, what falls first?

2. 3 lizards on a ceiling, 2 are fighting, 1 is watching them fighting. In the end all 3 lizards falls down from the ceiling. Why the 3rd lizard who watching the other 2 lizards fighting falls too?(no the 2 lizards who fought dosen't touch the 3rd lizards who is watching)

3. A room with two stories, upstairs and downstairs. 3 lights at upstairs and 3 switches at downstairs. How do you know which switch is for which light as you only allowed to go upstairs once and come back down once?

happy guessing!!
p.s. will post more soon if you guys still want more!

[hsadan]

2. 3 lizards on a ceiling, 2 are fighting, 1 is watching them fighting. In the end all 3 lizards falls down from the ceiling. Why the 3rd lizard who watching the other 2 lizards fighting falls too?(no the 2 lizards who fought dosen't touch the 3rd lizards who is watching)

the 3rd one laughs so hard when the other 2 fall that it itself falls:lol:

[McGiver]

1) the plane ;P
3) enlight 2 lights, switch one off again after some time, walk upstairs.
You'll have 1 lamp burning, 1 lamp that's warm, and 1 lamp that's cold

[ViNc3]

allo, i have 3 questions(not maths, but kinda logic):

1. An airplane(flying in mid-air) ran out of fuel, what falls first?

...

happy guessing!!
p.s. will post more soon if you guys still want more!

1. The fuel indicator thing

PS: Nice one for #3 McGiver :)

[McGiver]

Actually I heard #3 before

[Ψ]

7 cans upside down?

well the answer is 7up cans

[hsadan]

3) enlight 2 lights, switch one off again after some time, walk upstairs.
You'll have 1 lamp burning, 1 lamp that's warm, and 1 lamp that's cold
you could also switch 2 on, then switch one off and go up immediately - 1 lamp will be on, and 1 lamp will be warmer than the other. this saves time :P

or also switch 1 on, then switch it off and switch on another and go up, you'll get the same results :huh:

[hydrowire]

ViNc3:
1. The fuel indicator thing
yup.


McGiver:
3) enlight 2 lights, switch one off again after some time, walk upstairs.
You'll have 1 lamp burning, 1 lamp that's warm, and 1 lamp that's cold


hsadan:
you could also switch 2 on, then switch one off and go up immediately - 1 lamp will be on, and 1 lamp will be warmer than the other. this saves time

or also switch 1 on, then switch it off and switch on another and go up, you'll get the same results
yes and yes.


hsadan:
the 3rd one laughs so hard when the other 2 fall that it itself falls
noo.

this is so fun!

[ViNc3]

well the answer is 7up cans

ohhh ic

[Ψ]

arrite guyz heres another one

If EELS + MARK + BEST + WARY = EASY
What does HELP + BARK + WARD + LEAD equal?

[protagonist]

Hard =)

Here's my explanation:

1. letter + 2.letter + 3.letter + 4.letter

[Ψ]

good you kirupans are smart.... well i ll give you another one

What can fill a room but takes up no space?

[firegambler]

Light
Music
Noise

[Ψ]

holy crap!!!!! what the hell man...you smart bastards

heres a really hard one

There's a certain 10-digit number where that the first digit is
equal to the number of zeros in the entire number, the second
number is the number of 1's in the entire number, and so on, to
where the 10th digit is the number of 9's in the entire number.
What is the number?

[protagonist]

would work with 6210001000

explanation: there are 6 zero's in the number, the number 1 occurs 2 times, the number 2 once, and the number 6 once as well...

[Ψ]

arrit men i give up you guyz are too smart...

you guyz post some riddles/ brain teasers

[brownie]

Which Sea has no shoreline?

[McGiver]

tennessea :P

[Ψ]

I have seven letters. The first two stand for a boy. The
first three stand for a girl. The first four stand for a brave boy. But all of
my letters stand for a brave girl. What word am I?

[lunatic]

he - her - hero - HEROINE! :beam:

[Ψ]

luni howd u guess so easily

well heres another one..
its pretty stupid but here it is
in 3 step how do u put an elephant into a fridge

a followup to that one is

how do u put a giraffe into a fridge in four easy steps

[jtnw]

1. Open the door, put the elephant in, and close the door.

2. Open the door, take the elephant out, put the giraffe in, and close the door.

jtnw

[Ψ]

how is this possible man....anyone else have any other ones...cuz i guve up....u guyz are too smart

[hydrowire]

i got one :)

theres a jungle meeting held, all animals atended except one, what is it?

[jtnw]

lol, it's the giraffe. ;)

jtnw

[Ψ]

lol, it's the giraffe.

jtnw

would u mind explaining how??

[jtnw]

It's still in the fridge. :lol:

jtnw

[thoriphes]

What is at the beginning of eternity, the end of time, the beginning of every end, and the end of every place?

[paradox244]

"e"
at the end of simple too :P

[thoriphes]

Yep, just one of those teasers that some people tend to think too much about. Just like this:

Tom's mom has 4 kids: Quarter, Dime, Nickel. What is the fourth kid's name?

[Kyri]

teehee...TOM!!!

[brownie]

If any one cares the sea that has no shoreline is the Sargasso Sea

[ViNc3]

I had this question this year (Year 8) for a maths competition.

When Indiana walks into a cave, the door shuts behind him. He looks around and sees a chest full of diamonds, emeralds, rubies and sapphires. There ais a set of scales near the chest. The following statements are written on the door:

Each jewel of the same type weighs the same.
No two different types of jewels weigh the same.
One sapphire weighs the same as one diamond and one emerald together.
Three diamonds weigh the same as one sapphire and one ruby
One sapphire weighs more than one emerald and three rubies.
Fourteen rubies weigh more than one sapphire.
The doors will open and all the jewels will be yours if at your first attempt your place one diamond on one tray and other types of jewel on the other tray to make the scales balance.


a) List the four types of jewel in order from heaviest to lightest.

b)If a diamond was placed on a tray of the scale, what should Indiana place on the other tray to open the door?
:bad:

Use Algebra. Eg: S = D + E and 3D = S + R

[johnlouis]

It's still in the fridge. :lol:

jtnw
i dont get it :puzzle:

[protagonist]

a.)
saphire (weights 11 rubies)
emerald (weights 7 rubies)
diamond (weights 4 rubies)
rubies (weight unknown ;))

b.) see above, 4 rubies will balance the scales

i'll post an explanation if i'm right and it's desired :)

[ViNc3]

that's right! :hr: how did you get that so quick?? :ear:

[protagonist]

i used a pen and paper ;)

i solved it that way:

14 rubies > 1 sapphire and 3 diamonds = 1 sapphire + 1 ruby
so
3 diamonds < 14 rubies + 1 ruby or
3 diamonds < 15 rubies or

1 diamond < 5 rubies

1 sapphire = 1 diamond + 1 emerald and 1 sapphire > 1 emeralds + 3 rubies
so
1 emerald + 3 rubies < 1 diamond + 1 emerald or

3 rubies < 1 diamond

since the whole system only works with full numbers:
if one diamond weights less than 5 rubies but more than 3 it has to weight 4 rubies ;)

[Celeste Y]

smarty pants
I still dont get the giraff one

[protagonist]

just read back a few posts, you'll find out :P

[johnlouis]

i have one really easy:
The day before yesterday, John was 9 yrs old. Next year he will be 12 yrs old. How is this possible?

[protagonist]

"yesterday" was the 31. december, john's birthday, "today" is the 1. january of a new year...
before his birthday john was nine, then in the same year, he turned ten, since it's 1. january "today", this year he'll be eleven, and next year he'll be twelve

[johnlouis]

thats right!

[Hans Kilian]

A man hangs up his hat. He then puts on a functioning blindfold, takes his rifle, walks 100 paces, turns around and puts a bullet through his hat.

How is that possible?

[brownie]

He hangs his hat on a post, holds his rifle in his right hand, his left hand holds the post. He walks 100 paces around the post.

Dead hat.

[Hans Kilian]

Almost... :)
He hangs his hat on the barrel of the rifle.

[thoriphes]

Almost... :)
He hangs his hat on the barrel of the rifle.
You know, people get arrested for that type of behavior.

[Celeste Y]

Ok, here's a math one.
Draw a table that is three squares wide and three down (like a noughts & crosses table):
[ ][ ][ ]
[ ][ ][ ]
[ ][ ][ ]
Now, using only the following numbers:
1 2 3 4 5 6 7 8 9 (you may only use them once)
Place them in the table, so the from left to right it equals 15:
[X][X][X]=15
[X][X][X]= 15
[X][X][X]=15

And the same from top to bottom, and diagonal as well.

(clue: the middle block is 5)

[ditt0]

8+1+6
3+5+7
4+9+2

[Celeste Y]

think your smart huh? How about this

Mary and Bob are lying dead on the floor. The window is open, and there is some glass, and water near thier bodies.
How did they die?

[amitgeorge]

think your smart huh? How about this

Mary and Bob are lying dead on the floor. The window is open, and there is some glass, and water near thier bodies.
How did they die?
amit had came to vist them last night and killed them with ice knife.

[Celeste Y]

nope. The door was locked, and didn't show signs of a break in, other then the window being open.
What about the glass?
(clue: there was a windy storm outside)

[ditt0]

Bob and Mary are fishes? and their tank got broken by the storm



think your smart huh? How about this

Mary and Bob are lying dead on the floor. The window is open, and there is some glass, and water near thier bodies.
How did they die?

[Celeste Y]

:party: we have a winner!:party:

Last one, and then I am out

A man lives on the 20 floor of his apartment. Everyday he goes into the elevator, pushes ground and goes to work.
In the evening, he goes back in to the elevator and pushes 15, gets out, and walks up the remaining 5 floors. He does this everyday.
Why?

[amitgeorge]

A man lives on the 20 floor of his apartment. Everyday he goes into the elevator, pushes ground and goes to work.
In the evening, he goes back in to the elevator and pushes 15, gets out, and walks up the remaining 5 floors. He does this everyday.
Why?
He is short

[Celeste Y]

:puzzle: ok.......what do you call a boomarang that is broken?:evil:

[annexion]

A stick?

[Celeste Y]

GRRRRRR:scream:

Well, since you guys are so smart, you come up with one!
:upset:
:P

[amitgeorge]

GRRRRRR:scream:

Well, since you guys are so smart, you come up with one!
:upset:
:P
A woman has 7 children, half of them are boys.
How can this be possible?

[Celeste Y]

one of them was born with both genitals?
she orginaly had 8, but had a miscarriage?
one of them changed sex?

[Celeste Y]

the woman is pregant with the eighth child?

[[m]]

They're all boys. :P

[[m]]

or: at least 4 are boys.

[[m]]

:party: we have a winner!:party:

Last one, and then I am out

A man lives on the 20 floor of his apartment. Everyday he goes into the elevator, pushes ground and goes to work.
In the evening, he goes back in to the elevator and pushes 15, gets out, and walks up the remaining 5 floors. He does this everyday.
Why?
And is obviously not very smart. ;)

[[m]]

edit - wrong forum.

[Celeste Y]

amitgeorge- was "m" right?
If so..."m" your it

[amitgeorge]

']They're all boys. :P
:party:We have a winner :party:

[Celeste Y]

You have to give me points for Originality

[amitgeorge]

Originality ?

i think i have seen these before a number of times.

-1 marks for lying

[amitgeorge]

FINISHED FILES ARE THE RE-
SULT OF YEARS OF SCIENTIF-
IC STUDY COMBINED WITH
THE EXPERIENCE OF YEARS.

count the F's in that sentence.

[hsadan]

six. :)

i know you were hoping i said three.

[Ψ]

how are there six??

[lunatic]

FINISHED FILES ARE THE RESULT OF YEARS OF SCIENTIFIC STUDY COMBINED WITH THE EXPERIENCE OF YEARS.

Funny, I didn't see any of the "OF"s the first 10 times I looked at that sentence!

:hr:

[Laslett]

Funny, I didn't see any of the "OF"s the first 10 times I looked at that sentence!

:hr:


I think thats the point its trying to illustrate

[lunatic]

Right, I'm just explaining it to _azzy_ . . .

[Ψ]

wow that soo cool are u sure he didnt edit the post like right after i read it.
cuz i read it like 50 times and didndt see 6 fs


arrite heres a r riddle..

whats a lumberjacks favourite month?

[amitgeorge]

i give myself +32.73 for a great brain teaser .... so now the scores are :

Celeste Y -1
amit george +32.73 :lol:

Lumberjack hmmm...

january ?

just guessing

[Celeste Y]

hey........:*( Why do I get only minus one? I should get 100 for effort:pleased:

I have heard that lumberjack one before.......*scratches head* cant remember the answer....

[Celeste Y]

wasn't the answer something corney, like Oak-tober.........

[amitgeorge]

i am sorry there is no re-evaluation.... :tie:

It is against company policy

you can try again by reappearing next year..

:to::hugegrin:

[Celeste Y]

:lol:

well then I better start studying:book: so I can be as clever as you geoge :nerd:

;P :D

[amitgeorge]

:lol:

well then I better start studying:book: so I can be as clever as you geoge :nerd:

;P :D
please do... otherwise we are an equal opportunity employer. We (by policy) do not discriminate on basis of sex, caste, creed, colour, race or sexual orientation... :king:

currently we have three openings available.... :beard:
1) Casual acquaintance
2) Friend
3) Close Buddy

kindly state your interest and domain expertise in whichever you feel is your best area....:tie:

please do not forget to mention your expected renumeration....

:beer::to:

[amitgeorge]

wasn't the answer something corney, like Oak-tober.........
or sep-timber ?

[Celeste Y]

please do... otherwise we are an equal opportunity employer. We (by policy) do not discriminate on basis of sex, caste, creed, colour, race or sexual orientation... :king:

currently we have three openings available.... :beard:
1) Casual acquaintance
2) Friend
3) Close Buddy

kindly state your interest and domain expertise in whichever you feel is your best area....:tie:

please do not forget to mention your expected renumeration....


Lol! :lol:

Would you like a copy of my CV/resume to go with that? :A+:

Dear George

I am applying for the job application as stated in Kirupa forum, for the post of buddy.
I feel that I would be most suited for the job, as I have good experience in this domain. I have already posted a total of 64 replies in the last 2 months, as well as been in second place for the kirupa site of the week award.
I am registered to more then 13 forums all over the world, all concerning with flash. I also have a good social life outside of kirupa.
I was class representative in grade 8 and nominated for prom queen in grade 11. I also attened a total of 4 maths Competitions held at the Universaty of Cape Town, came 3rd in a volleyball tournament and played baseball, basketball and volley ball during high school as well as being part of the drama club.
I love animals and children.

If you could inform me more about the job, you can contact me at kirupa forums. I look forward to hearing your response.

Regards

Celeste

P.S. I think sep-timber was right

[ViNc3]

A naked man was found dead in the middle of a desert with half a match. A few metres away was his clothes lying on the ground. How did that happen?

You can ask yes or no questions but i take ages to reply.. :mu:

[Ψ]

hmm lets see...
the half a match is there because the match is burnt. he is dead becaus ehe burnt himself using his clotles that he lit on fire.. then he ran screaming a few metres ad died

that sounds reasonable

[[m]]

A naked man was found dead in the middle of a desert with half a match. A few metres away was his clothes lying on the ground. How did that happen?

You can ask yes or no questions but i take ages to reply.. :mu:He died of an meteorite impact.

There is no teaser in that. It is not even funny. Ok, next one:

http://www.nobeliefs.com/puzzles/trig.jpg

So you think you're good at trigonometry? Find the diameter of the circle. With explanation!

[jtnw]

16". Since the lower left part is a rectangle (3 given right angles, the 4th is assumed) both diagonals are equal. Since the diagonal is the radius of the circle, twice that is the diameter.

jtnw

[Ψ]

but how do u noe that the dagonal is the radius of the circle

[jtnw]

Diagonals of a rectangle are equal, so the segment from the top-left to the bottom-right is the same as the segment from the top-right to the bottom-left. Since the latter's two end points are the center of the circle and a point on the circle, it is defined as the radius.

jtnw

[Ψ]

smart!!!

[amitgeorge]

Lol! :lol:

Would you like a copy of my CV/resume to go with that? :A+:

Dear George

I am applying for the job application as stated in Kirupa forum, for the post of buddy.
I feel that I would be most suited for the job, as I have good experience in this domain. I have already posted a total of 64 replies in the last 2 months, as well as been in second place for the kirupa site of the week award.
I am registered to more then 13 forums all over the world, all concerning with flash. I also have a good social life outside of kirupa.
I was class representative in grade 8 and nominated for prom queen in grade 11. I also attened a total of 4 maths Competitions held at the Universaty of Cape Town, came 3rd in a volleyball tournament and played baseball, basketball and volley ball during high school as well as being part of the drama club.
I love animals and children.

If you could inform me more about the job, you can contact me at kirupa forums. I look forward to hearing your response.

Regards

Celeste

P.S. I think sep-timber was right

Wow! :lol: this is comming up better than i thought. !!
----------------------------------------------------

Dear Celeste

Thank you for applying with us...

After reviewing your application we feel that indeed you are quite suitable.

There are some really good point that interest us.

64 replies in the last 2 months
second place for the kirupa site of the week award
a good social life outside of kirupa
nominated for prom queen in grade 11
Interest in sports
part of the drama club
Of these the points which have really caught our interest are points numbered 3 and 4.

However we would like to have a chat with you before we proceed any further...

At this juncture we feel it appropriate to tell you a little about the growth opportunities we have.

As earlier stated.... we have three openings available.... :beard:
1) Casual acquaintance
2) Friend
3) Close Buddy

Those who are selected can in due course of time be promoted higher in the hierarchy :

4) Flirtatious friend
5) Romantic associate
6) Love Interest
7) Life long Partner

We assure you there are no direct recruitments to any of these positions. And no candidate has yet been suitable enough for position 7.

We offer attractive remuneration can be discussed at a later stage.

Regards

AmitGeorge

[Celeste Y]

HAHA!!!:lol: Dear George

Thank you for response and interest in my application. Since you show an interest in point number 4 so much, I feel you should know I have been "discovered" by 3 modeling agencies in the last two years.
I am still interested in the post of buddy, but should tell you I am only able to be promoted to option 4 of Flirtatious friend due to location and the fact that I am already 5, 6, and 7 to a third party.

If you could inform me a little bit more about your company, it will be most
appreciated.

Regards

Celeste

----------------
On topic:
Albert is a keen dog admirer and over the years has had a number of dogs. He has had an Alsatian, a Dalmatian, a Poodle and a Great Dane, but not necessarily in that order. Albert had Jamie first. The Dalmatian was an adored pet before the Great Dane. Sammy, the Alsatian, was the second dog Albert loved. Whitney was housed before the Poodle and Jimmy was not a Great Dane. Can you tell each of the dogs' name and the order in which Albert had them?