concatenating three variables?

[waxpants]

It's another simple problem that has me stumped.

x = 1;
y = 2;
z = 3;

trace(x+y+z);

how do I get this to display "123" instead of "6"?

I've tried both eval and concat() and have failed to get either to work, not that they don't work, I'm sure it's just me.

[lunatic]

convert them to string first?

[Lindquist]

Basically, you're going to have to convert the numbers to strings (a series of characters). You can either declare them as strings initially:

var x:String = "1";
var y:String = "2";
var z:String = "3";

trace(x+y+z);


Or convert them to strings when you need them:



var x:Number = 1;
var y:Number = 2;
var z:Number = 3;

trace(String(x)+String(y)+String(z));

[ramie]

var output_string:String = String(x) + String(y) + String(z);
trace(output_string);

[ramie]

lol, you beat me to it lindquist :)

[waxpants]

trace(String(x)+String(y)+String(z));

beautiful!

Thankyou folks.

[Lindquist]

lol, you beat me to it lindquist :)
in the game of kirupa, speed is the key! ;)

[Smee]

You can also:


trace(""+x+y+z);